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Newbie. Hey!

knowitall
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Newbie. Hey!

Post by knowitall » Wed Mar 09, 2011 8:15 pm

I'm new here with a really nice freestyle.

I know everything about anything so ask me a question.

jaunty75
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Re: Newbie. Hey!

Post by jaunty75 » Thu Mar 10, 2011 6:06 am

knowitall wrote:I know everything about anything so ask me a question.
What is the air-speed velocity of an unladen swallow?

knowitall
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Re: Newbie. Hey!

Post by knowitall » Thu Mar 10, 2011 6:24 am

15 parsecs/sec

Next question please.

jaunty75
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Re: Newbie. Hey!

Post by jaunty75 » Thu Mar 10, 2011 6:28 am

Is that an African or European swallow?

knowitall
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Re: Newbie. Hey!

Post by knowitall » Thu Mar 10, 2011 9:46 am

Do I have to handhold you through the entire answer?

It's either depending upon the wind velocity and weight of the bird.

jaunty75
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Re: Newbie. Hey!

Post by jaunty75 » Thu Mar 10, 2011 9:48 am

knowitall wrote:Do I have to handhold you through the entire answer?
Yes!

knowitall
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Re: Newbie. Hey!

Post by knowitall » Thu Mar 10, 2011 11:50 am

jaunty75 wrote:
knowitall wrote:Do I have to handhold you through the entire answer?
Yes!
You see if I gave you the answer I would only feed you for a day but if I forced you to think for yourself then I would feed you for a lifetime. :lol:

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mmsstar
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Re: Newbie. Hey!

Post by mmsstar » Thu Mar 10, 2011 5:37 pm

How does that go?..........give a man a fish and you will feed him for a day. Give him the internet and he will starve to death :lol:
Drove an 06 LTD FWD from July 08 to August 10, moved on to a 2011 Flex

lkreykes
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Re: Newbie. Hey!

Post by lkreykes » Thu Mar 10, 2011 8:18 pm

wow, knowitall, you are pretty much arrogant. sorry but
knowitall wrote:I know everything about anything
sounds pretty greedy. just saying...
2009 Ford F150 XLT SuperCrew Cab 5.4L 4x4
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Sold 2005 Ford Freestyle Limited AWD
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knowitall
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Re: Newbie. Hey!

Post by knowitall » Thu Mar 10, 2011 8:39 pm

lkreykes wrote:wow, knowitall, you are pretty much arrogant. sorry but
knowitall wrote:I know everything about anything
sounds pretty greedy. just saying...
Every forum has a know it all. I'm just being honest about it. So who am i replacing here? :P

KAH
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Re: Newbie. Hey!

Post by KAH » Fri Mar 11, 2011 6:07 am

Your answer as shown is:

15 parsecs/sec

Please show your formula and
calculations used to arrive at that
answer.

Ken H.

knowitall
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Re: Newbie. Hey!

Post by knowitall » Fri Mar 11, 2011 8:08 am

KAH wrote:Your answer as shown is:

15 parsecs/sec

Please show your formula and
calculations used to arrive at that
answer.

Ken H.
Assuming that swallows travel in right angles and using the distance to the sun for relativity:

For a right triangle,

sinP = 1AU/d

where p is the parallax, 1 AU (149,600,000 km) is approximately the average distance from the Sun to Earth, and d is the average distance to the originating point of the swallow. Using small-angle approximations (valid when the angle is small compared to 1 radian),

sin x = x radians = x * 180/PI (degrees) = x * 180 * 3600/PI (arcseconds)

so the parallax, measured in arcseconds, is

p" = 1 AU / d * 180 * 3600/pi

If the parallax is 1", then the distance is

d = 1 AU * 180 * 3600/pi = 206,265 = 3.2616 ly = 1 parsec

From measureable data a swallow will travel an average 0.5 ft in 0.66 seconds and given that 1 parsec = 0.05 ft. Also assuming no friction then the average speed of a swallow is

(0.5 ft/ 0.66 sec) * (1 parsec/0.05 ft)= 15.15 parsecs / second

Class dismissed. Final exam will be next week. :lol:

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Re: Newbie. Hey!

Post by KAH » Fri Mar 11, 2011 8:08 pm

Bit of a small mistake here:

sinP = 1AU/d

You obviously have the relationship of
AU / d mixed up. Since you are assuming the AU to be relatively constant and then dividing it by the flight distance
then you have the Cotangent function, not the Sine.

Sorry, minus two points already.

Ken H.

WhoaTed
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Re: Newbie. Hey!

Post by WhoaTed » Sat Mar 12, 2011 10:26 am

What? I don't know that!!
Take care,
Ted

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knowitall
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Re: Newbie. Hey!

Post by knowitall » Mon Mar 14, 2011 5:52 am

KAH wrote:Bit of a small mistake here:

sinP = 1AU/d

You obviously have the relationship of
AU / d mixed up. Since you are assuming the AU to be relatively constant and then dividing it by the flight distance
then you have the Cotangent function, not the Sine.

Sorry, minus two points already.

Ken H.
Sorry I'm the teacher here and I determine what's right. :lol:

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